Introduction

While the side lengths of right-angled triangles can be worked out using Pythagoras' Theorem, trigonometry and SOHCAHTOA provides a means of relating side lengths to angles in the triangle.

There are three main trigonometric functions: sine (\(\sin\)), cosine (\(\cos\)), and tangent (\(\tan\)).

The \(\sin\), \(\cos\) and \(tan\) functions are sometimes referred to as ratios, because they don't depend on the absolute lengths of the triangle, but the ratios of lengths. This means that it is only necessary to have one set of trigonometric functions.

The figure below shows the relationship between side lengths and the angle \( \theta \) on a triangle embedded in a circle of radius 1. In this case, the hypotenuse has length 1, the side with length \( \cos \theta \) is adjacent to angle \( \theta \), and the side with length \( \sin \theta \) is opposite to angle \( \theta \).


The tangent function relation is not shown, but it is the ratio of the lengths of the side \(\sin \theta\) to the length of the side \(\cos\theta\), i.e. \( \tan\theta = \frac{\sin\theta}{\cos\theta}\).

The circle diagram is important because every right angled triangle can be scaled to a right angled triangle with a hypotenuse length of 1. Or in other words, every right angled triangle is similar to a right-angled triangle with a hypotenuse length of 1.

The figure below shows a right-angled triangle, with sides as marked. The opposite and adjacent sides are marked relative to angle A.

NOTE: The opposite and adjacent sides are swapped from the point of view of angle B.


Note that angle A corresponds to angle \( \theta \) in the circle diagram above.

The SOHCAHTOA trigonometric relations are as follows, from the point of view of angle A.

SOH: \( \cos A = \frac{\mathrm{adj}}{\mathrm{hyp}} = \frac{b}{c} \)

CAH: \( \sin A = \frac{\mathrm{opp}}{\mathrm{hyp}} = \frac{a}{c} \)

TOA: \( \tan A = \frac{\mathrm{opp}}{\mathrm{adj}} = \frac{a}{b} \)

The SOHCAHTOA relations from the point of view of angle B are as follows. Notice that the \(\mathrm{adj}\), \(\mathrm{opp}\) and \(\mathrm{hyp}\) relations are the same, but the sides they correspond to are different.

SOH: \( \cos B = \frac{\mathrm{adj}}{\mathrm{hyp}} = \frac{a}{c} \)

CAH: \( \sin B = \frac{\mathrm{opp}}{\mathrm{hyp}} = \frac{b}{c} \)

TOA: \( \tan B = \frac{\mathrm{opp}}{\mathrm{adj}} = \frac{b}{a} \)

NOTE:

  1. When doing these calculations, make sure the angle unit on your calculator is set correctly. All these calculations assume your angle unit is degrees. A quick test is to perform the calculation \(\cos 90\). If the answer is zero, the angle is set correctly.
  2. It is always possible to check your answers by drawing the triangle to scale using a ruler and protractor, and measuring the sides.
  3. The hypotenuse is always the longest side, and opposite the 90° angle.


Question 1

The triangle is shown below, with the relevant sides labelled in terms of their relationship to the angle.


The hypotenuse is 15 units long, and the unknown side is opposite the 30° angle, therefore the \(\sin\) function is the relation we need. The unknown side will be labelled \(a\).

\(\sin 30 = \frac{\mathrm{opp}}{\mathrm{hyp}} = \frac{a}{15} \rightarrow a = 15 \sin 30 = 15 \cdot 0.5 \) = 7.5 #.


Question 2

The triangle is shown below, with the relevant sides labelled in terms of their relationship to the angle.


The hypotenuse is 12.5 units long, and the unknown side is adjacent the 65° angle, therefore the \(\cos\) function is the relation we need. The unknown side will be labelled \(a\).

\(\cos 30 = \frac{\mathrm{adj}}{\mathrm{hyp}} = \frac{a}{12.5} \rightarrow a = 12.5 \cos 65 = 12.5 \cdot 0.4226 \) = 5.28 #.


Question 3

The triangle is shown below, with the relevant sides labelled in terms of their relationship to the angle.


The hypotenuse is length is unknown, and the known side is opposite the 44° angle, therefore the \(\sin\) function is the relation we need. The unknown side will be labelled \(h\).

\(\sin 44 = \frac{\mathrm{opp}}{\mathrm{hyp}} = \frac{120}{h} \rightarrow h = \frac{120}{\sin 44} = \frac{120}{0.694658} \) = 172.74 #.

Note that the hypotenuse is always the longest side in the triangle.


Question 4

The triangle is shown below, with the relevant sides labelled in terms of their relationship to the angle.


The hypotenuse is 5 units long, and the unknown side is opposite the 67.5° angle, therefore the \(\sin\) function is the relation we need. The unknown side will be labelled \(a\).

\(\sin 30 = \frac{\mathrm{opp}}{\mathrm{hyp}} = \frac{a}{5} \rightarrow a = 5 \sin 67.5 = 5 \cdot 0.9239 \) = 4.62 #.


Question 5

The triangle is shown below, with the relevant sides labelled in terms of their relationship to the angle.


The hypotenuse is 12 units long, and the unknown side is opposite the 17° angle, therefore the \(\cos\) function is the relation we need. The unknown side will be labelled \(a\).

\(\cos 17 = \frac{\mathrm{adj}}{\mathrm{hyp}} = \frac{a}{12} \rightarrow a = 12 \cos 17 = 12 \cdot 0.956304 \) = 11.48 #.

آخر تعديل: الأربعاء، 13 مايو 2020، 11:06 AM